Советы по Delphi
HEX -> Integer
Решение 1
| var i : integers : string;begin s := '$' + ThatHexString;i := StrToInt(a);end; |
Решение 2
| CONST HEX : ARRAY['A'..'F'] OF INTEGER = (10,11,12,13,14,15); VAR str : String; Int,i : integer;BEGIN READLN(str);Int := 0;FOR i := 1 TO Length(str) DOIF str[i] < 'A' THEN Int := Int * 16 + ORD(str[i]) - 48ELSE Int := Int * 16 + HEX[str[i]];WRITELN(Int);READLN;END. |
